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Jul 13, 2015 · Convert PDF to Word Using C# The first step will be to get the PdfBox package using the Nuget Package Manager. Now, import the following DLLs into your .cs file: The third step will be to install the DocX NuGet Package from the NuGet Package Manager: Let's read a PDF file and try to get the text from it.

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Real-number conductance and imaginary-number susceptance combine to form complex admittance, symbolized by the capital letter Y This is a complete expression of the extent to which a circuit allows ac to flow As the absolute value of complex impedance gets larger, the absolute value of complex admittance becomes smaller, in general Huge impedances correspond to tiny admittances, and vice versa Admittances are written in complex form just like impedances But you need to keep track of which quantity you re talking about! This will be obvious if you use the symbol, such as Y = 3 j05 or Y = 7 + j3 When you see Y instead of Z, you know that negative j factors (such as in the quantity 3 j 05) mean there is a net inductance in the circuit, and positive j factors (such as in the quantity 7 + j3) mean there is net capacitance Admittance is the complex composite of conductance and susceptance Thus, complex admittance values always take the form Y = G + jB When the j factor is negative, a complex admittance may appear in the form Y = G jB Do you remember how resistances combine with reactances in series to form complex impedances In Chaps 13 and 14, you saw series RL and RC circuits Did you wonder why parallel circuits were ignored in those discussions The reason was the fact that admittance, not impedance, is best for working with parallel ac circuits Resistance and reactance combine in a messy fashion in parallel circuits But conductance (G ) and susceptance (B ) merely add together in parallel circuits, yielding admittance (Y ) Parallel circuit analysis is covered in detail in the next chapter

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geodetic coordinates are often desired Longitude can be found explicitly from eqns (29-210) as = arctan2(y, x) Solution for h and can be computed by iteration as follows [92]: 1 Initialization: Let h = 0 = a x2 + y 2

matching section of transmission line The input impedance is Rin, the output impedance is Rout, and the characteristic impedance of the line is Zo

2 Perform the following iteration until convergence: sin( ) = = RN ( ) = h = z (1 e2 )RN + h atan((z + e2 RN sin( ))/p) a 1 e2 sin2 ( ) p RN cos( )

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where the eccentricity e is a de ning constant of the geodetic system as discussed in Section 2321 Although it is conceptually simpler to take the inverse sine in the second step, the presented algorithm has much faster convergence, as shown in the following example Example 22 Consider the inversion of the previous example in which [x, y, z]e = [ 2430601828, 4702442703, 3546587358] m Starting with an initial estimate of h = 00 m, the algorithm as written converges to centimeter accuracy (1 10 9 rads) in four iterations:

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These equations are valid at the frequency fo for which the line length measures 1 4 wavelength Sometimes, the word wavelength is replaced by the lowercase Greek letter lambda ( ), so you will occasionally see the length of a quarter-wave section denoted as (1 4) or 025 Neglecting line losses, the preceding relations hold at all odd harmonics of fo, that is, at 3fo, 5fo, 7fo, and so on At other frequencies, a quarter-wave section of line does not act as a transformer Instead, it behaves in a complex manner that is beyond the scope of this discussion Quarter-wave transmission-line transformers are most often used in antenna systems, especially at the higher frequencies, where their dimensions become practical A quarter-wave matching section should be made using unbalanced line if the load is unbalanced, and balanced line if the load is balanced A disadvantage of quarter-wave sections is the fact that they work only at specific frequencies But this is often offset by the ease with which they are constructed, if radio equipment is to be used at only one frequency, or at odd-harmonic frequencies

iteration lat: deg lat: min lat: sec h 1 34 0 0027145 2376519 2 34 0 0003159 2517325 3 34 0 0001738 2517020 4 34 0 0001740 2517020 5 34 0 0001740 2517020

The same algorithm with the same initial estimate for h, but using an inverse sine instead of an arctan function in the second calculation of the iteration has still not converged to meter level accuracy after eight iterations:

Problem 18-5 Suppose an antenna has a purely resistive impedance of 100 It is connected to a 1 4-wave section of 75- coaxial cable What is the impedance at the input end of the section Use the formula from above:

iteration lat:deg lat: min lat: sec h 1 34 2 3141 3401 2 33 58 5062 -1189 3 34 0 3177 912 4 33 59 4545 -50 5 34 0 667 390 6 33 59 5695 188 7 34 0 140 280 8 33 59 5936 238

R in = Z o2/R out = 752/100 = 5625/100 = 56

Convergence to centimeter accuracy requires 25 iterations Generally, the arctan-based iterative technique converges quickly, especially when a good initial guess at the solution (eg, from a previous measurement) is available

Various alternative approximate and closed form solutions exist in the literature [24, 66, 68, 76, 117]

Problem 18-6 Consider an antenna known to have a purely resistive impedance of 600 You want to match it to the output of a radio transmitter designed to work into a 500- pure resistance What is the characteristic impedance needed for a quarter-wave matching section Use this formula:

This section presents methods for transforming points and vectors between rectangular coordinate systems The axes of each coordinate system are assumed to be right-handed and orthogonal Three dimensions are used throughout the discussion; however, the discussion is equally valid for Rn

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Nov 8, 2012 · PDF Focus.Net - How to convert PDF to Word using C#. SautinSoft.Duration: 4:17 Posted: Nov 8, 2012

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